Answer:
the CPU utilization decreases as the degree of multiprogramming is increased.
Explanation:
The fundamental concept is that allocating a process with too few frames causes too many and frequent page faults. This implies that the CPU does not perform any useful work and thus its utilization would decrease drastically. In this case, the long-term scheduler, in a bid to improve the utilization of the CPU, would load more processes into the memory so as to increase the extent of multiprogramming. As a result, there would be more decrease in the utilization of the CPU, leading to a chained reaction of higher page faults, which is then followed by a corresponding increase in the multiprogramming degree, usually known as thrashing.
B. Because major shifts in thinking can cause change.
Answer:
True
Explanation:
in function guess:- a = x; b = y; c = z
so 45 > 31 AND 45 < 38
since both the stements are true
True is printed
Answer:
enables you to make changes to one part of an image without accidentally changing other parts
Explanation:
Computer aided designs incorporate the use of multiple layers in drawings. The first layer is known as the layer 0, while the present layer the designer is working on is known as the current layer. The advantage of the incorporation of layers in designs include the following
1. It helps objects to be altered, grouped, hidden and moved as the designer wishes.
2. Layers can be grouped and worked on separated and common properties like color and line weight assigned to them.
3. Layers can be manipulated as the user wishes. They can be locked, frozen, turned off, etc. Locking prevents accidental changes being made on objects.
Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.