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mariarad [96]
3 years ago
5

Help me with systems of linear equations

Mathematics
1 answer:
harina [27]3 years ago
4 0
What do u need help with?
You might be interested in
Please help!
il63 [147K]

Answer:

The answer to your question is:  1287

Step-by-step explanation:

Data

          ₁₃C₅

Formula

                    C = \frac{n!}{k!(n- k)}

                 

                    C = 1287

6 0
3 years ago
Complete the following problem and round to the correct number of significant figures:
Tpy6a [65]
11.85 which rounds to 12, 12 should be the correct answer
6 0
3 years ago
Tim and Tom are trying to earn money to buy a new game system over a 3-month period. Tim saved $45.14 each month. If they need a
Ivahew [28]
The correct answer is C:$76.05. Tim would make 135.42 in three months and the total  (221.47) minus 135.42 equals 76.05.
6 0
3 years ago
Read 2 more answers
What ratio is equivalent to 8:3
Georgia [21]

16:6 is an equivalent ratio

5 0
3 years ago
Read 2 more answers
Write the standard form of a line that passes through (1, 1) and (3, 4)
Sophie [7]

Answer:

3x - 2y = 1

Step-by-step explanation:

Step 1:   Find the slope

slope m = (y2 - y1)(/x2 - x1)

 m = (4 - 1)/(3 - 1) = 3/2

Step 1:  Use the formula y = mx + b to solve

This is slope-intercept form of a line.  We have a slope of 3/2, and a point (x, y), which is (1, 1).  Plug those values into the equation above and solve for b (the only variable we are missing

1 = (3/2)(1) + b

   1 = 3/2 + b  

          1 - 3/2 = b

             2/2 - 3/2 = b

                  -1/2 = b

Step 2: Rewrite the formula using the slope and the b value we just calculated

 y = (3/2)x - 1/2

Step 3:  Standard form of a line is ax + by = c, where a is a positive integer, so we rearrange the equation from step 2 to standard form.  

y = (3/2)x - 1/2

 -(3/2)x + y = -1/2     (subtract (3/2)x from both sides)

 

      -3x + 2y = -1       (multiply by 2 to get rid of the fraction on x)

           3x - 2y = 1     (multiply by -1 so a becomes positive)    

3 0
3 years ago
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