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NemiM [27]
3 years ago
8

Exponents and roots are what operations

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

An exponent

Step-by-step explanation: So if we have 83, we want to multiply three 8s, or 8 * 8 * 8. A root is basically the opposite. We're trying to find the number that we multiply by itself a certain number of times to get the number under the radical sign.

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Please help me this is due today
Evgen [1.6K]
Split the room into 2 rectangles 
area =  5*4 + 3*3  = 29 sq ft

So the cost is 29*8 =  $232
6 0
3 years ago
WILL GIVE BRAINLIEST The angle of elevation from Ben to the top of a telephone pole is 62 degrees. If Ben is standing 8 feet fro
MrRissso [65]

Answer: The height of the telephone pole = $15.046

Step-by-step explanation:

Given: Angle of elevation= 62 degrees.

Distance of Ben from the base of the pole = 8 feet

According to trigonometry, we have

\tan x=\dfrac{\text{side opposite to x}}{\text{side adjacent to x}}

i.e.

\tan 62^{\circ}=\dfrac{\text{ height of the telephone pole}}{8}\\\\(1.880726)=\dfrac{\text{ height of the telephone pole}}{8}\\\\\text{ Height of the telephone pole} = 8\times 1.880726\approx15.046

Hence, The height of the telephone pole = $15.046

4 0
2 years ago
If de has endpoints D(-1,6)and E(3,-2),then the midpoint M of DE lies in Quadrant1
SVETLANKA909090 [29]
M(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) \\M(\frac{-1 + 3}{2}, \frac{6 + (-2)}{2}) \\ M(\frac{2}{2}, \frac{6 - 2}{2}) \\ M(1, \frac{4}{2}) \\ M(1, 2)
7 0
3 years ago
In science and engineering, radians are much more convenient and common than degrees. what is the degree value for one radian ?
sveticcg [70]

Answer:

57.3

Step-by-step explanation:

just took the quiz

4 0
2 years ago
Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod
goblinko [34]

(2+3)^{-1}\equiv5^{-1}\pmod7 is the number <em>L</em> such that

5L\equiv1\pmod7

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

2a\equiv1\pmod7\implies a\equiv4\pmod7

since 2*4 = 8, whose residue is 1 mod 7;

3b\equiv1\pmod7\implies b\equiv5\pmod7

which we got for free by finding the inverse of 5 earlier. So

2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0
3 years ago
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