My apologies on answering late...
Same situation as the previous problem, but this time, all you need to do is state the degree of the angle instead of just providing the angle itself.
ΔABC ≅ ΔDEF
Now, we can see that ∠C ≅ ∠F. Using this information, we can find ∠C on the first triangle ( which is
° ).
Since ∠C ≅ ∠F,
m∠F is
°.
Hope I caught your question in time!
Have a good one! If you need anymore help, let me know.
Answer:
744 in³
Step-by-step explanation:
Since you are filling the larger box with both rectangular prism and Styrofoam peanuts, you need to find the overall volume of the larger box and subtract the volume of the glass box to find the amount of space that the Styrofoam peanuts need to take up.
Volume (prism) = Bh, where B = area of the base, h = height
Larger Box: V = 10 x 10 x 15 = 1500 in³
Glass Box: V = 7 x 9 x 12 = 756 in³
1500 - 756 = 744 in³ of Styrofoam peanuts
Answer:
1. Choice B
2. Choice C
3. X=-2
4. Choice A
5. y = 5/2 x + 5
Step-by-step explanation:
1.
the slope is down 3 over 2 m =-3/2
point slope form
y-y1= m (x-x1)
y-y1 = -3/2 (x-x1)
Choice B
2. (-3,-1) (1/2,2)
slope = (y2-y1)/(x2-x1)
m=(2--1)/(1/2--3) = (2+1)/(1/2+3) = 3/(3.5) = multiply top and bottom by 2
m = 6/7
point slope form
y-y1 = m(x-x1)
y--1 = 6/7 (x--3)
y+1 =6/7 (x+3)
multiply by 7
7y+7 = 6(x+3)
7y+7 = 6x+18
subtract 7y from each side
7 = 6x-7y+18
subtract 18 from each side
-11=6x-7y
Choice C
3. x=-2
This is a vertical line, the value of x never changes
4. (-1,2) (1,-4)
slope =(y2-y1)/(x2-x1)
= (-4-2)/(1--1) = -6/(1+1) = -6/2 = -3
point slope form
y-y1 = m(x-x1)
y-2 = -3(x--1)
y-2 = -3(x+1)
y-2 = -3x-3
add 2 to each side
y = -3x-1
Choice A
5. (-2,0) (0,5)
the y intercept is 5
slope is change in y over change in x
slope =(y2-y1)/(x2-x1) = (0-5)/(-2-0) = -5/-2 = 5/2
slope intercept form
y= mx+b
y = 5/2 x + 5
Tbh depends how big the plate it
Answer:
(1) the whole is the sum of its parts
Step-by-step explanation:
This isn't using a property of equality. Instead, it's stating that the whole (MP) is the sum of its two parts (MN and NP).