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Alex73 [517]
4 years ago
14

Gianna invested $30,000 in an account paying an interest rate of 1.9% compounded

Mathematics
1 answer:
Ganezh [65]4 years ago
3 0

Answer:

5,095,068

Step-by-step explanation:

The equation for this problem is x^y * z where x is the percentage, Y is the number of years, and Z is the original deposit. Multiply 1.9^8 * 30,000 which becomes; 5,095,068.

Whoever has that bank account is going to be very rich.

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1) C

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3 years ago
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4 years ago
Which of the following relations is a function?
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5 0
3 years ago
If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193 how much was your original deposit? 29 Origin
Wittaler [7]

Answer:

The original amount deposit is $1641627.68.

Step-by-step explanation:

Given : If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193.

To find : How much was your original deposit?  

Solution :

Applying interest formula,

A=P(1+r)^t

Where, A is the amount i.e. A=$3783193

P is the principal value i.e. the original deposit

r is the interest rate r=11%=0.11

t is the time t=8 years.

Substitute the value in the formula,

3783193=P(1+0.11)^8

3783193=P(1.11)^8

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P=\frac{3783193}{2.30}

P=1641627.68

Therefore, The original amount deposit is $1641627.68.

3 0
3 years ago
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