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Alex73 [517]
3 years ago
14

Gianna invested $30,000 in an account paying an interest rate of 1.9% compounded

Mathematics
1 answer:
Ganezh [65]3 years ago
3 0

Answer:

5,095,068

Step-by-step explanation:

The equation for this problem is x^y * z where x is the percentage, Y is the number of years, and Z is the original deposit. Multiply 1.9^8 * 30,000 which becomes; 5,095,068.

Whoever has that bank account is going to be very rich.

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4 0
2 years ago
Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
Katarina [22]

After 4 interval of six months, Joe to earn same hourly rate as Blaine

<em><u>Solution:</u></em>

Given that,

Amount earned by Joe = $ 14 per hour

Amount earned by Blaine = $ 18 per hour

Lets assume the number of six month intervals be "x"

<em><u>Joe receives a raise of $1.75 every six months</u></em>

Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

<em><u>Blaine receives a raise of $0.75 every six months</u></em>

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

14+1.75x = 18+0.75x\\\\1.75x-0.75x = 18-14\\\\1x = 4\\\\x = 4

Thus after 4 interval of six months, Joe to earn same hourly rate as Blaine.

8 0
3 years ago
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