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vesna_86 [32]
2 years ago
13

HELP PLS I CAnt DO THIS

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
5 0

Using the two given solutions and the general absolute value function we will get:

|x + 9|  = 27

<h3>Which absolute value function has that solution set?</h3>

The two solutions are:

x = 0 and x = -18.

Remember that the absolute value equation is something like:

|x - a| = b

If we want to have these solutions, then:

|0 - a| = b

|-18 -a| = b

From the first one, we have:

|-a| = b

Replacing that on the second equation we get:

|-18 -a| = |-a|

Notice that if we take a = -9, then we have:

|-18 + 9| = |+9|

|-9| = |+9|

This is true, so a = -9.

Then we find the value of b:

|18 + 9| = b = 27

Then the absolute value equation is:

|x + 9|  = 27

If you want to learn more about absolute value equations, you can read.

brainly.com/question/3381225

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A car that originally cost $20,000 depreciates by 15% each year in about how many years will be car be worth half its value use
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3 years ago
Suppose that the functions p and q are defined as follows.
inessss [21]

The most appropriate choice for function can be given by

qop(3) =  \sqrt{15}+1

poq(3) =  2\sqrt{3} + 10

What is function?

A function from A to B is a rule that maps to each element of A a unique element of B.

A is called the domain of the function and B is called the co domain of the function.

We can do addition, subtraction, multiplication, division and composition on functions.

Let f and g be two functions

fog(x) = f(g(x)) and gof(x) = g(f(x))

This is known as composition of function.

Here,

p(x) = x^2 + 6\\q(x) = \sqrt{x} +1

qop(x) = q(p(x))

          =q(x^2+6)

          = \sqrt{x^2+6}+1

qop(3) = \sqrt{3^2+6}+1

          = \sqrt{15}+1

poq(x) = p(q(x))

          = p(\sqrt{x}+1)

          = (\sqrt{x}+1)^2+6

          = x + 1 + 2\sqrt{x} + 6

          = x + 2\sqrt{x} +7

poq(3) = 3 + 2\sqrt{3}  +7

               2\sqrt{3} + 10

               2\sqrt{3} + 10

To learn more about functions, refer to the link:

brainly.com/question/10439235

#SPJ9

7 0
1 year ago
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