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Alexeev081 [22]

3 years ago

7

Write the equation of a line with a slope of −2 and a y-intercept of 5. (2 points) Question 1 options: 1) −2x + y = 5 2) 2x − y

= 5 3) y = −2x + 5 4) y = 5x − 2

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

Answer:

3 is the answer

Step-by-step explanation:

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Rs = 8y + 4 , ST = 4y + 8 , and RT = 36 , find the value of y

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I assume that you meant RS and ST are segments of RT. If that is true then:

RS+ST=RT, using the values for these given...

8y+4+4y+8=36 combine like terms on left side

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Answer:

Correct Option is d $(x+3)^2 = 11$

Step-by-step explanation:

For completing the square our equation should be in the form of $a^2 +2ab + b^2 = (a+b)^2$

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$x^2 +6x -2\\x^2 + 2(x) (?) +(?)^2 = 2\\for\,\, making\,\, 6x\,\, 2*x*3=6x \\so, \,\,we\,\, can\,\, add\,\, and\,\, subtract\,\, (3)^2 \,\,on\,\, both\,\, sides\\x^2 + 2(x) (3) +(3)^2 -(3)^2= 2\\(x+3)^2 -9 =2\\(x+3)^2 =2+9\\(x+3)^2 = 11$

Correct Option is d $(x+3)^2 = 11$

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