Answer:
2=x
Step-by-step explanation:
-2x+5=4x-7
+2x +2x
5=6x-7
+7 +7
12=6x
/6
2=x
It has been proven that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
<h3>How to prove a Line Segment?</h3>
We know that in a triangle if one angle is 90 degrees, then the other angles have to be acute.
Let us take a line l and from point P as shown in the attached file, that is, not on line l, draw two line segments PN and PM. Let PN be perpendicular to line l and PM is drawn at some other angle.
In ΔPNM, ∠N = 90°
∠P + ∠N + ∠M = 180° (Angle sum property of a triangle)
∠P + ∠M = 90°
Clearly, ∠M is an acute angle.
Thus; ∠M < ∠N
PN < PM (The side opposite to the smaller angle is smaller)
Similarly, by drawing different line segments from P to l, it can be proved that PN is smaller in comparison to all of them. Therefore, it can be observed that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
Read more about Line segment at; brainly.com/question/2437195
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Yes here multiply takes place not divide
Answer:
x = 11º
Step-by-step explanation:
1. Notice Parallel Lines
2. Understand Angle Relationships When Parallel Lines Are Present (e.g., alternate interior/exterior)
3. ∠CAB ≅ ∠DCA ∴ m∠CAB = 33º
4. Use exterior angle theorem: the sum of non-adjacent angles of the same triangle which the exterior angle is drawn is equal to the measure of that angle.
5. Therefore write and solve the equation 2x + 33º (sum of non-adjacent interior angles) = 5x (exterior angle).
- 2x + 33 = 5x (C.L.T or <u>C</u>ombine <u>L</u>ike <u>T</u>erms)
- 3x = 33 (inverse operations; divide by 3)
- x = 11º (remember to apply units)