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3 years ago

PLEASE HELP !!!!!!!!!!

Mathematics

1 answer:

Grace [21]3 years ago

3 0

Answer:

y = -0.5x

Step-by-step explanation:

To write the equation of the line, use the formula y = mx where m is the slope. Find the slope by subtracting the x and y coordinates. Use the formula below:

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{2--1}{-4 - 2} = \frac{3}{-6} = -\frac{1}{2}$

Since the slope is -1/2 or -0.5, this means the equation of the line is y = -0.5x.

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M <1 = 30°, m< 2 = 45°, m<3=

Papessa [141]

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3 years ago

Number 3.

Sergio039 [100]

Answer:

see explanation

Step-by-step explanation:

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∠ PXQ = 42° ( alternate angle theorem )

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3 years ago

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Mumz [18]

Answer:

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3 years ago

If m∠2 = 23° and m∠3 = 68°, what is m∠1

Harrizon [31]

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Step-by-step explanation:

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5 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago

PLEASE HELP !!!!!!!!!!​

PLEASE HELP !!!!!!!!!!