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anastassius [24]
2 years ago
9

2. On vacation, Katelyn wanted to have her hair braided in multiple braids to cover her head. The beautician charges a flat rate

of $4, plus $0.75 per braid. She's saved $29 to get braids. How many braids can she get?​
Mathematics
2 answers:
ElenaW [278]2 years ago
6 0

Answer:

33 braids

Step-by-step explanation:

What you want to do is first put in the equation. You put in 0.75x + 4=29.

Then you subtract 4 from 29 and get 25. Then divide 25 by 0.75 and you get the answer 33.3333333333. Round it to the nearest whole number and you get the final answer of 33 braids.

scoundrel [369]2 years ago
4 0
29 = 4 + .75b
subtract 4
25 = .75b
divide .75
b = 33.3333333
b = 33 braids
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They will actually be charged $10 exactly.

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If a square has breath of 13 cm what would be the lenght and perimeter ?​
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20 Ib/day = ____ oz/h
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5 0
3 years ago
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Consider the following dot plots.
MrRa [10]
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7 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
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