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Goshia [24]
3 years ago
7

Find the value of x in the triangle shown below

Mathematics
1 answer:
Trava [24]3 years ago
4 0

Answer:

62 degrees

Step-by-step explanation:

As two sides shown are same in length thus angle containing by them will be also same.

Thus, other unmarked angle will also be x degrees.

one angle is 56 degrees

we know that sum of angle of triangle is 180 degrees.

Thus

x + x + 56 = 180

2x + 56 = 180

2x = 180 - 56 = 124

x = 124/2 = 62

Thus, value of x is 62 degrees.

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Write the inequality for the graph
Svetach [21]

Answer:

x≤-2

Step-by-step explanation:

it would be that because if the graph is going to the left that means it is less than x and the opposite is for greater than. Now if there is a closed circle that means the sign is equal to hence the line under the sign. So therefore it's x≤-2

5 0
3 years ago
Alex and glen share a 30 ounce bucket of clay by the end of the week alex has used 1/10 of the bucket and glen has used 2/5 of t
Mamont248 [21]

Answer:

21 ounces

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6 0
2 years ago
Given: -1/4x > 4. Choose the solution set.
vampirchik [111]

Answer:

x < -16, none of the solution sets are correct for the given equation.

Step-by-step explanation:

-1/4x > 4, multiply both sides by -4, don't forget when you multiply or divide by a negative you have to flip the sign.

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none of the solution sets are correct for the given equation.

5 0
3 years ago
What is the product of 3 1/2 x 1/5
vesna_86 [32]

Answer:

7/10

Step-by-step explanation:

8 0
3 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
2 years ago
Read 2 more answers
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