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Gnom [1K]
3 years ago
11

HELP I NEED TO DO THIS NOW I NEED ANSWER B AND C

Mathematics
1 answer:
Tanzania [10]3 years ago
6 0

Answer: a = 13 b = 39 c = 12

Step-by-step explanation:

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If you wanted to know how big the tiger is, which measurments would you use?
Andreas93 [3]

the answer you are looking for is C

6 0
3 years ago
From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of \mu and its 90% margin of error.

b. A 95% confidence interval for \mu.

Answer:

a

\= x  = 13.4   .   E = 2.3

b

10.7 <  \mu < 16.1

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

       \= x  = \frac{11.1 + 15.7 }{2}

=>    \= x  = 13.4

Generally the margin of error is mathematically evaluated  as

     E = \frac{15.7 - 11.1}{2 }

=> E = 2.3

  From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

      \= x  -  Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1

=> 13.4   -  0.3877 s  = 11.1

=>  s = 5.932

  From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

=>    E =  2.7      

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

3 0
3 years ago
K - 4.8=0.32 - 5.4k answer?
RSB [31]

Answer:

k =4/5

Step-by-step explanation:

k - 4.8=0.32 - 5.4k\\\mathrm{Multiply\:both\:sides\:by\:}100\\k\times\:100-4.8\times\:100=0.32\times\:100-5.4k\times\:100\\\\Refine\\100k-480=32-540k\\\\Add\: 480\mathrm{\:to\:both\:sides}\\100k-480+480=32-540k+480\\\\Simplify\\100k=-540k+512\\\\\mathrm{Add\:}540k\mathrm{\:to\:both\:sides}\\100k+540k=-540k+512+540k\\\\Simplify\\640k=512\\\\\mathrm{Divide\:both\:sides\:by\:}640\\\frac{640k}{640}=\frac{512}{640}\\\\k=\frac{4}{5}

5 0
3 years ago
For the formula F = 95K – 455.67, what is the value of K when F = 0?
Inessa [10]

Answer:

<em>K = 4.8</em>

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

F = 95K - 455.67

We are required to find the value of K when F=0:

95K - 455.67 = 0

Adding 455.67:

95K = 455.67

Dividing by 95;

K = 4.8

4 0
3 years ago
Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit. Total
Andrews [41]
Jill had a total score of 40 on 13 quizzes, so her average was
  40/13 ≈ 3.08

_____
1 quiz @ 1 = total of 1
3 quizzes @ 2 = total of 6
4 quizzes @ 3 = total of 12
4 quizzes @ 4 = total of 16
1 quiz @ 5 = total of 5
total score = 1 + 6 + 12 + 16 + 5 = 40
total quizzes = 1 + 3 + 4 + 4 + 1 = 13
8 0
3 years ago
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