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3 years ago

What number is 4 times as many as 25

2 answers:

6 0

This is a standard relationship/systems of equations question. Here is how you attack it. Firstly, set up equations to represent the relationships. Ed = 4*Kim That shows that Ed has four times as many pins as Kim. Next, we see that the two have 25 together. So: Ed + Kim = 25 Now we have our two equations. In order to solve, we need to get one of the equations down to one variable. We can achieve this via substitution. The first equation tells us that we can substitute 4*Kim for Ed (in the second equation). So, let's do just that: 4*Kim + Kim = 255*Kim = 25Kim = 5 Using the first equation again, we can solve for Ed: Ed = 4*KimEd = 4*(5)<span>Ed = 20</span>

Debora [2.8K]3 years ago

3 0

Just multiply 4 by 25. You get 100.

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the cost of an ice cream sundae is 4.75$ plus 30 cents per topping. megan spends $6.26 on her sundae how many toppings did he ge

alexgriva [62]

Answer:

Step-by-step explanation:

$4.75 + 0.3x = $6.26

0.3x = 1.51

x = 5.033

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3 years ago

How many 4 digits codes can be formed with odd numbers without repetition? 0 is not allowed.

Sliva [168]

9514 1404 393

Answer:

120

Step-by-step explanation:

The number of permutations of 5 things taken 4 at a time is 120.

There are 5 odd digits. You want to choose 4 of them, then arrange those 4 in all possible ways. There are 5·4·3·2 = 120 ways to do that.

120 4-digit codes can be formed using odd digits with no repetition.

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3 years ago

N independent random samples of 10 men and 10 women in a coed basketball league, the numbers of points scored per season are giv

faltersainse [42]

Answer:

Step-by-step explanation:

Hello!

To compare both datasets I've made a box plot for them.

The yellow one belongs to the points scored by the men and the green one is for the points scored by the women.

Women: The box seems symmetrical, the median and the mean (black square) are almost the same. The whiskers are almost the same length, you could say that in general the points scored by the women have a symmetrical distribution.

Men: The box looks a little skewed to the right, the median is closer to the 1st quantile and the mean is greater than the median. The whiskers are the same length, in general the distribution seems almost symmetrical.

As you can see in the box plot the median and mean of the points scored by the women are almost the same. Using the data I've calculated both values:

Me= 24.50

X[bar]= 23.80

The median divides the sample in halves (50-50), it shows you where the middle of the distribution is.

The average shows you the value that centers the distribution, meaning, it is the value around which you'll find most of the data set. It summarizes best the sample information and therefore is a better measure of center.

As you can see in the box plots, there are no outliers in both distributions.

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.

Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:

X < Q₁ - 1.5 IQR

X > Q₃ + 1.5 IQR

Or extreme outliers if:

X < Q₁ - 3 IQR

X > Q₃ + 3 IQR

For the women data set:

Q₁= 17; Q₃= 30; IQR= 30 - 17= 13

Lower outliers: X < Q₁ - 1.5 IQR= 17-1.5*13= -2.5 ⇒ The minimum value recorded is 03, so there are no outliers.

Upper outliers: X > Q₃ + 3 IQR= 30 + 1.5*13= 49.5 ⇒ The maximum value registered is 41, so there are no outliers.

I hope this helps!