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Aleksandr [31]
3 years ago
12

What number is 4 times as many as 25

Mathematics
2 answers:
Oduvanchick [21]3 years ago
6 0
This is a standard relationship/systems of equations question.  Here is how you attack it.  Firstly, set up equations to represent the relationships. Ed = 4*Kim That shows that Ed has four times as many pins as Kim.  Next, we see that the two have 25 together.  So: Ed + Kim = 25 Now we have our two equations.  In order to solve, we need to get one of the equations down to one variable.  We can achieve this via substitution.  The first equation tells us that we can substitute 4*Kim for Ed (in the second equation).  So, let's do just that: 4*Kim + Kim = 255*Kim = 25Kim = 5 Using the first equation again, we can solve for Ed: Ed = 4*KimEd = 4*(5)<span>Ed = 20</span>
Debora [2.8K]3 years ago
3 0
Just multiply 4 by 25. You get 100.
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coldgirl [10]

\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2} \times (30 \times h) \\  \\  \leadsto \frac{1}{2}   \times 30h \\  \\  \leadsto  \frac{1}{ \cancel{2}} \times  \cancel{30}h \\  \\  \leadsto1 \times 15h \\  \\  \leadsto \: h = 15 \: yd

Therefore, the require height is 15 yd.

\green\starProof:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2}  \times (30 \times 15) \\  \\  \leadsto \frac{1}{ \cancel{2}}   \times  \cancel{450} \\  \\  \leadsto1 \times 225  \\  \\  area = 225  {yd}^{2}

\boxed{ \frak \red{brainlysamurai}}

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1 year ago
Write an equation to show "three times a number is 11".
Charra [1.4K]

Answer:

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A triangle has one side that is 6 units long and another side that is 3 units long.
kiruha [24]

The possible value of the third length is an illustration of Triangle inequality theorem

The possible third lengths are 4 units and 6 units

<h3>How to determine the possible length of the third side?</h3>

To determine the third length, we make use of the following Triangle inequality theorem.

a + b > c

Let the third side be x.

So, we have:

x + 6 > 3

x + 3 > 6

3 + 6 > x

Solve the inequalities

x > -3

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Remove the negative inequality value.

So, we have:

x > 3 or x < 9

Rewrite as:

3 < x or x < 9

Combine the inequality

3 < x < 9

This means that the possible value of the third length is between 3 and 9 (exclusive)

Hence, the possible third lengths are 4 units and 6 units

Read more about Triangle inequality theorem at:

brainly.com/question/2403556

5 0
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