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Romashka-Z-Leto [24]
2 years ago
5

Alan has scored 99, 85, and 74 on his previous three tests. What score does he need on his next test so that his average (mean)

is 83?
Mathematics
1 answer:
Alenkinab [10]2 years ago
8 0
(99+85+74+x)/4=83
multiply both by 4
99+85+74+x= 332
258+x=332
subtract 258 both sides
x= 74

He must get a 74.

To check answer:
99+85+74+74= 332
332/4 = 83

It’s right!

Hope it helps
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a person invested $6700 for one year, part at 8%, part at 10%, and the remainder at 12%. the total annual income from these inve
lukranit [14]

Answer:

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

Step-by-step explanation:

step 1

Let

x-----> the amount invested at 8% rate

y-----> the amount invested at 10% rate

z-----> the amount invested at 12% rate

z=(x+y)+300 ----> equation A

x+y+z=6,700 ----> equation B

substitute equation A in equation B

x+y+(x+y+300)=6,700

2x+2y=6,400

x+y=3,200 -----> equation C

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=1\ year\\ P=\$6,700\\ I=\$716

substitute in the formula above

716=x(0.08)+y(0.10)+z(0.12)

substitute equation A

716=x(0.08)+y(0.10)+(x+y+300)(0.12)

716=0.08x+0.10y+0.12x+0.12y+36

716=0.20x+0.22y+36

0.20x+0.22y=680  -----> equation D

step 2

Solve the system of equations

x+y=3,200 -----> equation C

0.20x+0.22y=680  -----> equation D

Solve the system by graphing

The solution is the point (1,200,2,000)

see the attached figure

Find the value of z

z=(x+y)+300

z=(1,200+2,000)+300=3.500

therefore

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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