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3 years ago

Divide squared 9x^2 by squared 18y^2

Mathematics

2 answers:

koban [17]3 years ago

7 0

$\frac{\sqrt{9x^2}}{\sqrt{18y^2}}=\frac{x\sqrt{3^2}}{y\sqrt{3^2*2}}=\frac{\not3x}{\not3y\sqrt2}=\frac{x}{y\sqrt2}=\frac{x}{y\sqrt2}*\frac{\sqrt2}{\sqrt2}=\frac{x\sqrt2}{2y}$
Answer = C

MAVERICK [17]3 years ago

3 0

Answer(C)

√(9x^2)= 3x
√(18y^2)=3y/√2= 3y/√2 X √2/√2
=3√2y/2

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2 years ago

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aleksandrvk [35]

Answer: -2 4/15

Step-by-step explanation: To properly subtract, we need to find a common denominator. We can list the multiples of 3 and 5 to find the common denominator:

3: 3, 6, 9, 12, 15

5: 5, 10, 15

The first common multiple we see is 15.

Calculation:

3 · 3 = 9

9 + 1 = 10

3 1/3 = 10/3

5 x 5 = 25

25 + 3 = 28

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Now to convert into fifteen as the denominator:

-28/5 = -28 x 3/5 x 3 = -84/15

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1 year ago

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Vlad1618 [11]

Answer:

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Step-by-step explanation:

Given:

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We need to find the product of two numbers in Scientific notation.

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Number of decimal point moved needs to be counted. This number is b.

If decimal are moved to the left b is positive.

If decimal are moved to the right b is negative.

If decimal are not moved b = 0.

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Hence the product is;

$97\times4.3\times 10^4 = 417.1 \times 10^4$