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Oxana [17]
2 years ago
10

A rectangular classroom has an area of 300 square feet. The length of the classroom is 5 feet longer than the width, w. Create a

n equation in terms of w to model this situation. Then, rewrite the equation in standard form and use the quadratic formula to solve for w.
Mathematics
1 answer:
weqwewe [10]2 years ago
6 0

Answer:

w^2 + 5w = 300

Step-by-step explanation:

A= length x width

A =300

Width = w

length = w + 5

Therefore

300 = (w) x (w + 5)

300 = w^2 + 5w

w^2 + 5w = 300

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Which is more 2 yards or 40 inches
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3 0
2 years ago
Twice as many students are in the chess club as in the fencing club.The number of students in the fencing club is one fifth the
jekas [21]

Answer:

28 students

Step-by-step explanation:

Let number of students in cooking club = x

Number of students in fencing club = 1/5 x

Number of students in chess club = 2(1/5)x

Since, There are 42 more students in the cooking club than in the chess club

Then ;

Number of students in chess club = Number of students in cooking club - 42

2(1/5)x = x - 42

(2/5)x - x = - 42

(2/5)x - x = - 42

-0.6x = - 42

x = 42 / 0.6

x = 70

Hence, number of students in chess club :

(2/5) * 70 = 28

4 0
2 years ago
7(1 - 76) - 2b = -197
noname [10]

Answer:

b= -164

Step-by-step explanation:

calculate the difference

7x(-75)-2b= -197

multiply the numbers

-525-2b= -197

move the constant to the right- hand side and change the sign

-2b= -197+525

add

-2b=328

divide

b= -164

4 0
3 years ago
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