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Zina [86]
3 years ago
13

*LAST QUESTION , PLEASE ANSWER TY* (: Quadrilateral ABCD is inscribed in a circle. If angle A measures (3x – 10)° and angle C me

asures (2x)°, find x.

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Quadrilaterals.

Basically we know that, the sum of opposite angles of a quadrilateral inscribed in a circle is always 180°.

so applying this law here, we get as,

2X + (3X-10) = 180°

=> 5X - 10° = 180°

=> 5X = 190°

=> X = 190°/5

=> X = 38°

thus the angle X= 38°.

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The total bill for a dinner,before tax,is $50.00.if you leave an 18% tip,you will leave a tip of?
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Then you will leave a tip of $9

because 0.18x50=9

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4 years ago
Solve the equation.<br> 2(x + 4) = 30<br> A. 7 <br> B. 11 <br> C. 15 <br> D. 19
evablogger [386]
If you would like to solve the equation 2 * (x + 4) = 30, you can calculate this using the following steps:

2 * (x + 4) = 30
2 * x + 2 * 4 = 30
2 * x + 8 = 30
2 * x = 30 - 8
2 * x = 22    /2
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The correct result would be B. 11.
5 0
3 years ago
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The absolute value of the lowest elevation in California is greater than the absolute value of the lowest elevation in Illinois.
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Each day, X arrives at point A between 8:00 and 9:00 a.m., his times of arrival being uniformly distributed. Y arrives independe
astraxan [27]

Answer:

Y will arrive earlier than X one fourth of times.

Step-by-step explanation:

To solve this, we might notice that given that both events are independent of each other, the joint probability density function is the product of X and Y's probability density functions. For an uniformly distributed density function, we have that:

f_X(x) = \frac{1}{L}

Where L stands for the length of the interval over which the variable is distributed.

Now, as  X is distributed over a 1 hour interval, and Y is distributed over a 0.5 hour interval, we have:

f_X(x) = 1\\\\f_Y(y)=2.

Now, the probability of an event is equal to the integral of the density probability function:

\iint_A f_{X,Y} (x,y) dx\, dy

Where A is the in which the event happens, in this case, the region in which Y<X (Y arrives before X)

It's useful to draw a diagram here, I have attached one in which you can see the integration region.

You can see there a box, that represents all possible outcomes for Y and X. There's a diagonal coming from the box's upper right corner, that diagonal represents the cases in which both X and Y arrive at the same time, under that line we have that Y arrives before X, that is our integration region.

Let's set up the integration:

\iint_A f_{X,Y} (x,y) dx\, dy\\\\\iint_A f_{X} (x) \, f_{Y} (y) dx\, dy\\\\2 \iint_A  dx\, dy

We have used here both the independence of the events and the uniformity of distributions, we take the 2 out because it's just a constant and now we just need to integrate. But the function we are integrating is just a 1! So we can take the integral as just the area of the integration region. From the diagram we can see that the region is a triangle of height 0.5 and base 0.5. thus the integral becomes:

2 \iint_A  dx\, dy= 2 \times \frac{0.5 \times 0.5 }{2} \\\\2 \iint_A  dx\, dy= \frac{1}{4}

That means that one in four times Y will arrive earlier than X. This result can also be seen clearly on the diagram, where we can see that the triangle is a fourth of the rectangle.

6 0
3 years ago
the runner's time to complete the marathon is 45 minutes. The time to complete the last marathon was 49.5 minutes. What is the p
Lana71 [14]

Answer:

9.09%

Step-by-step explanation:

To find percent decrease you have to use this equation:

Percent Decrease = \frac{Initial -New}{Initial} x 100

Initial = 49.5

New = 45

Plug in and solve:

PD = \frac{49.5-45}{49.5} x 100\\\\PD = \frac{4.5}{49.5} x 100 \\\\PD = 0.0909 x 100\\\\PD = 9.09

The percent decrease is 9.09%

<em>Hope this helps!!</em>

<em>- Kay :)</em>

6 0
3 years ago
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