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3 years ago

How do I do this ? I don’t understand logarithm

Mathematics

1 answer:

ale4655 [162]3 years ago

8 0

Hello from MrBillDoesMath!

Answer:

x = 19

Discussion:

Both sides are logarithms to the same base, namely 20 , which implies the expressions in x (what we are taking logarithms of) must be equal. So we need to solve

4x - 10 = 3x + 9 => subtract 3x from both sides

4x-3x - 10 = 9 => add 10 to both sides

x = 9 + 10 = 19

Thank you,

MrB

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Answer:

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Step-by-step explanation:

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3 years ago

Can anyone help me about question 2

madreJ [45]

9514 1404 393

Answer:

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Step-by-step explanation:

Using logarithms base 2, we have ...

$(a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}$

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

$\log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}$