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pashok25 [27]
3 years ago
7

Proof David Berkowitz is a psychopath 25 points + marked brainiest!

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

According to the “Hare Psychopathy Checklist” a psychopath is a person who knows right from wrong in our society but often feels no guilt, remorse or empathy when they engage in wrong actions. They lie easily, blame others for their actions and often hurt people who are close to them. David Berkowitz meets the criteria of Hare’s checklist and is believed to be a true psychopath. Berkowitz is known as the “Son of Sam”, a thrill seeking serial killer who terrorized the city of New York for over a year. Information about David Berkowitz’s background, personality traits and lifestyle and his serial killer profile help to prove that he is in fact a psychopath. In conclusion, this essay will prove to readers that David Berkowitz is a notorious…

Step-by-step explanation:

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Exercise 1.2 1 Round each of these numbers to the degree of accuracy shown in brackets. a) 7765 (nearest hundred). b) 1099 (near
wlad13 [49]

Answer:

a. 700

b. 1000

c. 80

d. 700

e.

6 0
1 year ago
**HELP!!!!** ILL GIVE BRAINLIEST
Step2247 [10]

The value of n such that the number n and -3/4 are additive inverses is 3/4

<h3>How to determine the value of n?</h3>

The statement is given as:

The number n and -3/4 are additive inverses

The above statement means that

n = -1 * -3/4 --- by the definition of additive inverses

Next, we evaluate the product of -1 and -3/4

n = 3/4

Hence, the value of n such that the number n and -3/4 are additive inverses is 3/4

Read more about additive inverses at

brainly.com/question/1548537

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8 0
1 year ago
7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

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5 0
2 years ago
A(x-y) + b (x-y) factorize​
Andre45 [30]

Answer:Given expression : a(x-y)-b(x-y)

Now, (x-y) is common in both terms.

First factor is (x-y).

∴a(x−y)−b(x−y)=(x−y)(a−b)

If you are reading this hope you have a wonderful day and may your dreams come true!

Good luck

4 0
2 years ago
The endpoints of EFare E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of EF?
jekas [21]
<span>The coordinates of the midpoint of EF is ((xE + xF)/2, (yE + yF)/2)
The third option is the correct answer.
</span>
3 0
3 years ago
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