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2 years ago

Find X, AB, BC, and AC if ABC is equilateral. X = AB = BC = AC =

Mathematics

1 answer:

Lemur [1.5K]2 years ago

3 0

X=-7
AB=-37
BC=73
AC=-49
I pretty sure

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5x - 2y = 10 x + 4y = 2

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Answer:

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Step-by-step explanation:

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2 years ago

(assume no variable equals 0) PLEASE HELP

saw5 [17]

$(3n^2 + 1) + (8n^2 - 8)\\= 3n^2 + 1 + 8n^2 - 8\\= 11n^2 - 7$

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2 years ago

You just reflected on working with right triangles and trigonometric concepts. How important were concepts that you learned prev

harina [27]

Idk if ya still need it or if this will help but this is what i put for mine

Concepts that I had previously learned about are quite important because math goes hand and hand. if you try to skip something and go ahead you'll most likely get confused because there could of been something highly important to that would help you understand whats ahead. in the previous unit it tells you about triangles and their description like a right triangle-90 degree angle and where legs and hypotenuse is located, this unit has had a ton about right triangles.

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2 years ago

A tank fills in 8 hours but evaporates in 12. how long will it take to fill the tank

Neko [114]

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2 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

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2 years ago

Find X, AB, BC, and AC if ABC is equilateral. X = AB = BC = AC = ​

Find X, AB, BC, and AC if ABC is equilateral. X = AB = BC = AC =