Question

Find u and v only please:

Answer 1

Every two triangles are similar. Therefore the sides of triangles are in proportion.

We have the equations:

1.

$\dfrac{3}{5}=\dfrac{3+x}{20}$    cross multiply

$5(3+x)=(3)(20)$      divide both sides by 5

$3+x=(3)(4)$

$3+x=12$      subtract 3 from both sides

$\boxed{x=9}$

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2.

$\dfrac{3}{4}=\dfrac{9}{y}$      cross multiply

$3y=(4)(9)$

$3y=36$      divide both sides by 3

$\boxed{y=12}$

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3.

$\dfrac{3}{5}=\dfrac{3+9+u}{60}$

$\dfrac{3}{5}=\dfrac{12+u}{60}$    cross multiply

$5(12+u)=(3)(60)$      divide both sides by 5

$12+u=(3)(12)$

$12+u=36$      subtract 12 from both sides

$\boxed{u=24}$

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4.

$\dfrac{3}{4}=\dfrac{24}{v}$              cross multiply

$3v=(4)(24)$

$3v=96$      divide both sides by 3

$\boxed{v=32}$