assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
1 answer:
Given:
x and y are both differentiable functions of t.


To find:
The value of
.
Solution:
We have,
...(i)
At x=-1,




Divide both sides by 3.

Taking cube root on both sides.

So, y=2 at x=-1.
Differentiate (i) with respect to t.

Putting x=-1, y=2 and
, we get



Divide both sides by -8.


Therefore, the value of
is 36.
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