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Otrada [13]
2 years ago
6

Suppose "35" cars start at a car race. In how many ways can the top 3 cars finish the​ race?

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
7 0

Answer:

The  value  is   \left 35  } \atop }} \right. P_3  =  39270

Step-by-step explanation:

From the question we are told that

    The  total number of cars is  n  =  35

     The  number cars considered is  r = 3

Generally the number of different top three finishes possible for this race of 35 cars  is mathematically represented as

       \left n } \atop }} \right. P_r  =   \frac{n!}{(n - r) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35! }{(35 - 3) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35 *  34 *  33 *  32! }{32 !}

       \left 35  } \atop }} \right. P_3  =  39270

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