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Otrada [13]
3 years ago
6

Suppose "35" cars start at a car race. In how many ways can the top 3 cars finish the​ race?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

The  value  is   \left 35  } \atop }} \right. P_3  =  39270

Step-by-step explanation:

From the question we are told that

    The  total number of cars is  n  =  35

     The  number cars considered is  r = 3

Generally the number of different top three finishes possible for this race of 35 cars  is mathematically represented as

       \left n } \atop }} \right. P_r  =   \frac{n!}{(n - r) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35! }{(35 - 3) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35 *  34 *  33 *  32! }{32 !}

       \left 35  } \atop }} \right. P_3  =  39270

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The two properties newton used to rewrite the <em>expression </em>are;

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  • This involves algebraic <em>properties</em>. There are 3 major types that work on only addition and multiplication namely;

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Let us define each of them;

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2) Commutative Property; This property means that we can change the

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3) Distributive Property; This property means that multiplying the sum of

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Newton has the expression; (4 × 23) × 25

Since it is multiplication, he can use any of the three properties above but let us use the <em>associative and distributive properties </em> as they are most suited to this expression<em>.</em>

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(4 × 23) × 25 = (25 × 4) + (25 × 23)

Read more at; brainly.com/question/20724601

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Step-by-step explanation:

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