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3 years ago

What is the area of the parallelogram?

Mathematics

1 answer:

nevsk [136]3 years ago

7 0

The length of the parallelogram is 3/4 ft less 1/8 ft, or 6/8 ft less 1/8 ft, or 5/8 ft.

The width is 1/2 ft.

Thus, the area is (5/8 ft)(1/2 ft) = (5/16) ft^2

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11. Sara borrowed *60,000 from a money lender at 15% rate of interest per annum. What is

patriot [66]

Answer:

36000

Step-by-step explanation:

Given the following

Principal = 60,000

Rate = 15%

Time = 4years

Using the simple interest formula

SI = PRT/100

SI = 60000*15*4/100

SI = 600 * 60

SI = 36,000

Hence the interest paid after 4 years is 36000

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3 years ago

Scarlett can make 7 cupcakes (the y value) with one cup of flour (the x value). How many cupcakes can she make with 9 cups of fl

HACTEHA [7]

Answer:

63=x*y

Step-by-step explanation:*

y = 7 x=1. so 9 will muiltiply 7 until there is 9 7s then you got the answer

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3 years ago

If f(x) = 2x - 4 and g(x) = x^2+3, find each value. 19. (f - g)(x) 20. (f • g)(x)

just olya [345]

Step-by-step explanation:

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3 years ago

Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r

erastova [34]

Answer:

The probability is $\frac{56!}{64!}$

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, $64 \choose 8 .$

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function $f : A \rightarrow A ,$ with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

$\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}$

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3 years ago

katelyn bought 5.68 pounds of peaches. the peaches were on sale for 1.49 a pound. how much did lately spend on peaches

Leya [2.2K]

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3 years ago

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