Charles drew a regular hexagon and divided it into two identical trapezoid the diagonal shown in 30 is 32 cm Charles measure the
height of one the trapezoid and found that the height was 13.9 cm find the area of the
1 answer:
Answer:
669cm2
Step-by-step explanation:
Answer:
correct question
Charles drew a regular hexagon and divided it into two identical trapezoid , the side length of the hexagon iscoming16cm,the diagonal shown in fig 30 is 32 cm Charles measure the height of one the trapezoid and found that the height was 13.9 cm find the area of the area
Step-by-step explanation:
The side length of the hexagon should be given which is 16 cm
To get the Length the side lenght makes with the height of the trapezium, Pythagoras theorem is applied to get the base of the triangle
Base = √((16)^2 - (13.9)^2
Base = √62.29
Base = 7.92cm
Since we have gotten the base
Diagonal - the base gives the top length of the trapezium.
32- 7.92- 7.92 = 16.16
The area of the hexagon gives the 2 times of the trapezium.
To find the area of the trapezium
= 1/2 * ( a+b)h
= 1/2* ( 32+ 16.16)* 13.9
= 24.04*13.9
Area of th trapezium = 334.71cm2
= 334.71 * 2
= 669.42cm2
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