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steposvetlana [31]
4 years ago
10

Eleven less than a number is more than seventeen in number form

Mathematics
1 answer:
Olegator [25]4 years ago
5 0
-11+n>17
add 11 to both sides
11-11+n>17+11
0+n>28
n>28
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find thge length of the line segment with endpoints (7,2) and (-4,2), and explain how you arrived at your solution.
nirvana33 [79]
Since they have same y (2), it means this is a straight line.  what you need to do is just find the distance between -4 and 7. distance between -4 and 7 is 7-(-4)= 11

8 0
3 years ago
During an experiment, Mrs. Melsoner uses an analytical scale to measure the mass of a substance. The analytical scale says she h
stich3 [128]

Answer:

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7 0
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zvonat [6]
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5 0
3 years ago
) Elise has put 5 cans (all of the same size) on her kitchen counter; 2 cans of vegetables, 2 cans of soup , and 1 can of peache
Anvisha [2.4K]

Answer:

0.7 = 70%.

Step-by-step explanation:

There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:

C(5,2) = 5!(3!*2!) = 5*4/2 = 10

To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:

There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:

C(3,2) = 3!/2! = 3

So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7

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4 0
3 years ago
PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!
irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem.  So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor.  The quotient is (x-6) and the remainder is 13 according to the problem.  So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13.  That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get \frac{x^3}{13} we cannot reduce it so it is not a fraction so 13 is not a factor of P

None of these is the right option.

4 0
3 years ago
Read 2 more answers
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