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Mama L [17]
3 years ago
8

The area of a square is numerically equal to twice the primeter.find the length of a side of the square.

Mathematics
2 answers:
just olya [345]3 years ago
8 0

Answer:

a = 8

Step-by-step explanation:

Gwar [14]3 years ago
3 0
The length of one side is 4 units
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Need help please can you give answer with working out i can not answer as it is quite gard
Elis [28]

Step-by-step explanation:

\text{Given:}\\\\AB=3x-4\\AC=2x+12\\BC=7x-2\\AB:AC=1:2\Rightarrow(3x-4):(2x+12)=1:2\\\\\dfrac{3x-4}{2x+12}=\dfrac{1}{2}\qquad\text{cross multiply}\\\\(3x-4)(2)=(2x+12)(1)\qquad\text{use the distributive property}\\\\(3x)(2)+(-4)(2)=2x+12\\\\6x-8=2x+12\qquad\text{add 8 to both sides}\\\\6x-8+8=2x+12+8\\\\6x=2x+20\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\6x-2x=2x-2x+20\\\\4x=20\qquad\text{divide both sides by 4}\\\\\dfrac{4x}{4}=\dfrac{20}{4}\\\\x=5

\text{Put the value of}\ x\ \text{to}\ AC\ \text{and}\ BC:\\\\AC=2(5)+12=10+12=22\\\\BC=7(5)-2=35-2=33\\\\AC:BC=22:33=\dfrac{22}{33}=\dfrac{22:11}{33:11}=\dfrac{2}{3}=2:3

4 0
3 years ago
Slove this for me please​
Alborosie

Answer:

-10

Step-by-step explanation:

divide both sides by -4

simplify to v+8=-2

subtract 8 from both sides

v=-10

6 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7B4%7D%20%3D%20%5Cfrac%7Bb%7D%7B7%7D" id="TexFormula1" title="\frac{a}{4} =
tamaranim1 [39]

Answer:

Step-by-step explanation:

\frac{a}{4}=\frac{b}{7}\\a=\frac{4b}{7} \\\frac{a-b}{b} =\frac{\frac{4b}{7}-b }{b} \\=\frac{4b-7b}{7b}\\ =\frac{-3b}{7b}\\ =\frac{-3}{7}

6 0
3 years ago
HELP PLEASE NEED IT
dem82 [27]

Answer:

256 degrees.

Step-by-step explanation:

The figure is a parallelogram so m < 1 = 180-52 = 128 degrees (same side angles).

Also m < 2 = m < 1  (opposite angles of a parallelogram), so their sum is 2*128

= 256 degrees.

6 0
3 years ago
You drop a ping pong ball into a measuring cup. The water started at 200 mL but after you drop the ping pong ball the water rise
sveta [45]

Answer:

200

Step-by-step explanation:

4 0
3 years ago
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