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NeTakaya
4 years ago
14

Nick has tennis practice every sixth day. Mark has tennis practice every 4th day. On July 31st they both had tennis practice. Wh

en will be the next time that they both have practice on the same day?
Mathematics
1 answer:
Montano1993 [528]4 years ago
3 0

Nick has tennis practice every sixth day = 6

Mark has tennis practice every 4th day = 4

They both had tennis practice on = 31st July

We have to find when will be the next time that they both have practice on the same day?

For this, we will find the LCM of 4 and 6

So, LCM of 4 and 6 is 12.

So, it will be 12 days after 31st July, that they will practice on the same day.

So it is 12th August.


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One side of a rectangle is 9 millimeters shorter than six times the other side. Find the length of the longer side if we also kn
vodka [1.7K]

Given:

W(width) = (6L) - 9

L(length) = L

Equation:

2( [ 6L ] - 9) + 2 (L) = 150

= 12L - 18 + 2L = 150

= 12L + 2L = 150 + 18

=14L = 168

L = 168/14, so the length is 12. Let's check our work.

Width:  6(12) - 9 = 72 - 9 = 63

Length: 12

Since there are two lines of width and two lines of length:

2(12) + 2(63) = 24 + 126, which gives you a perimeter of 150 mm.

Hope this helped.

4 0
3 years ago
Which is the better by 3 pounds for $8.31 or 5 pounds for $12.95 explain
sleet_krkn [62]
Do $8.31/3 and $12.95/5 and that will give you a price per pound and whichever is cheaper would be a better deal.
6 0
3 years ago
Which linear equation represents the data given in the table?
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The answer is C y=6x-6
6 0
3 years ago
You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an
Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

Calculate the final value with the formula:

M=P_{}(1+i)^n

Substituting:

\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

i = 3.75 / 100 = 0.0375

n = 3

Calculating:

\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}

The third investment is in a stock plan. The initial value of the investment is

P = 20% of $20,000 = $4,000

By the end of the first year, the stock plan increased by 8%, thus its value is:

M1 = $4000 * 1.2 = $4,800

By the end of the second year, the stock plan decreased by 4$, thus the value is:

M2 = $4,800 * 0.96 = $4,608

Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

3 0
1 year ago
C) Bhurashi can do 1/3 part of a work in 6 days.
Simora [160]

Answer:

<h2>i. 18 days</h2><h2>ii.\frac{1}{18} part of work</h2><h2>iii. \frac{1}{2} part of work</h2><h2 />

Step-by-step explanation:

i.

\frac{1}{3} part of work can be done in 6 days.

Days taken to complete the whole work:

= 6 * 3

= 18 days

ii. Whole work will be done in 18 days.

So, 1 day work = \frac{1}{18}

iii. Work done in 9 days :

\frac{1}{18}  \times 9

=  \frac{1}{2}

So, remaining work :

1 -  \frac{1}{2}

=  \frac{1 \times 2 - 1}{2}

=  \frac{2 - 1}{2}

=  \frac{1}{2} part of work

Hope this helps...

Good luck on your assignment..

8 0
4 years ago
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