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4 years ago

If you go to the gym 4 times per week how many times in 10 weeks

Mathematics

1 answer:

VashaNatasha [74]4 years ago

4 0

The answer is 40. If you go 4 times per week in 10 weeks you will go 10*4=40.

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The square root of 31 is between which two numbers !!! ILL GIVE YOUU A BRANLIESTTT!!

ad-work [718]

Answer:

The square root of 31 is 5.5 (not including numbers after that, just those two work) therefore it's in between the two numbers of 5 and 6.

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3 years ago

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Nailah bought an ice cream cake all for herself. The cake costs $30. There is a 15% discount for all ice cream cakes. How much i

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Answer:

C $3 discount

Step-by-step explanation:

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3 years ago

3X to the second power plus 5x plus y

disa [49]

Answer:

3x²+5x+y

Step-by-step explanation:

The word form is converted to an equation

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3 years ago

What is the corresponding congruent part for each segment or angle?<br> Suppose △JXP≅△MQB

nadezda [96]

JP=MB
XP=QB
P=B
J=M

This is because every letter in the triangle notation is respective to one another

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3 years ago

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Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

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3 years ago