All categories

3 years ago

Help with algebra 2 test please and thank you

Mathematics

1 answer:

loris [4]3 years ago

3 0

Answer:

w=63

Step-by-step explanation:

1. Multiply both sides by 2

2. square both sides

At this point, you should have this:

w+1=64

Subtract 1 from both sides.

w=63

HTH, good luck :)

You might be interested in

A) 3d = 2d - 2<br><br>B) 5d = 4d - 4

scZoUnD [109]

Answer:

3D= -2

5D= -4

Step-by-step explanation:

3D = 2d -2

3d - 2d = -2

d= -2

5d =4d-4

5d - 4d = -4

d = -4

hope it will help you

7 0

3 years ago

Guys help i cant figure this out I'm stressing please help me

Mashcka [7]

Answer:

C) 0.066...

Step-by-step explanation:

1/15 = 0.066...

You could eliminate B and C as 15 (numerator from question) is not a multiple of 10. You can eliminate A as the numerator of 15 from the question is larger than 10 and will result in a number less than 0.1.

4 0

3 years ago

Can you help me I need to send this to my teacher like TODAY

Rashid [163]

Coordinates when you see t

8 0

2 years ago

Read 2 more answers

The medical laboratory claim that the mean turn-around time for the performance of the battery of tests on blood sample is 1.005

Shkiper50 [21]

Answer:

Hi mate

Step-by-step explanation:

Please broswer se search karo

7 0

3 years ago

A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

kondor19780726 [428]

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

$^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15$

Hence , the number of different combinations of 2 vegetables are possible = 15 .

5 0

3 years ago