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3 years ago

(2.5×10-8)(9×10-10)

Mathematics

1 answer:

IgorC [24]3 years ago

4 0

Answer:

1360

Step-by-step explanation:

First, you do all the operations inside the parenthesis, and then you multiply the two. Also, remember the order of operations. Multiplication always comes before addition and subtraction.

(2.5x10-8)(9x10-10)

(25 - 8)(90 - 10)

(17)(80) = 17x80 = 1360

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Fiona is trying to prove that a pair of expressions are equivalent by using substitution. Which pair of expressions has the same

fiasKO [112]

Missing Part of the Question

3 (4 - y) -7 ; 5 + 3y

9 + y + 4y - 2 - 3y; -2y + 7

5 + y - 2 - 6y + y; 8y + 3

2y + 7 + y - 2 + y; 4y + 5

Answer:

2y + 7 + y - 2 + y; 4y + 5

Step-by-step explanation:

Given

y = 3

Required

Which pair of expression are equal

To get the pair of expression that are equal; we simply substitute 3 for y in each of the expressions

3 (4 - y) -7 and 5 + 3y

Substitute 3 for y in 3 (4 - y) -7

This gives 3(4 - 3) -7

= 3(1) - 7

= 3 - 7

= -4

Then Substitute 3 for y in 5 + 3y

This gives 5 + 3(3)

= 5 + 9

= 14

-4 and 14 are not equal

---------------------------------------------------------------------------------------

9 + y + 4y - 2 - 3y; -2y + 7

Substitute 3 for y in 9 + y + 4y - 2 - 3y

This gives 9 + 3 + 4(3) - 2 - 3(3)

= 9 + 3 + 12 - 2 - 9

= 13

Then Substitute 3 for y in -2y + 7

This gives -2(3) + 7

= -6 + 7

= 1

13 and 1 are not equal

---------------------------------------------------------------------------------------

5 + y - 2 - 6y + y; 8y + 3

Substitute 3 for y in 5 + y - 2 - 6y + y

This gives 5 + 3 - 2 - 6(3) + 3

= 5 + 3 - 2 - 18 + 3

= -9

Then Substitute 3 for y in 8y + 3

This gives 8(3) + 3

= 24 + 3

= 27

-9 and 27 are not equal

---------------------------------------------------------------------------------------

2y + 7 + y - 2 + y; 4y + 5

Substitute 3 for y in 2y + 7 + y - 2 + y

This gives 2(3) + 7 + 3 - 2 + 3

= 6 + 7 + 3 - 2 + 3

= 17

Then Substitute 3 for y in 4y + 5

This gives 4(3) + 5

= 12 + 5

= 17

17 and 17 are equal

Hence, Option D is correct

6 0

3 years ago

At Information and Communications University: 31 female seniors were on the dean’s list 62 women were on the dean’s list who wer

inessss [21]

Step-by-step explanation:

There's a lot of information here, so first things first, let's get organized.

Let's start by assigning variable names to each group. We want the variables to be short but easy to understand.

For example, let's say the number of female seniors on the dean's list is FSD (F for female, S for senior, and D for dean's list).

FSD = 31

Sticking to this naming scheme:

FD = 62

MSD = 45

FS = 87

MS = 96

F = 275

MD = 88

M = 227

Now we can begin.

a) We want to know how many seniors there are. So all we have to do is add up all the variables with an S in them.

FSD + MSD + FS + MS

31 + 45 + 87 + 96

259

b) We want to know how many women there are. So add up all the variables with an F in them.

FSD + FD + FS + F

31 + 62 + 87 + 275

455

c) We want to know how many are on the dean's list. So add up all the variables with a D in them.

FSD + FD + MSD + MD

31 + 62 + 45 + 88

226

d) Now we want to know how many are seniors AND on the dean's list. So add up all the variables that have both an S and a D.

FSD + MSD

31 + 45

e) We want to know how many female seniors there are, so add up all the variables with both an F and an S.

FSD + FS

31 + 87

118

f) We want to know how many women were on the dean's list, so add up all the variables with both an F and a D.

FSD + FD

31 + 62

g) Finally, we want to know how many students there are total. So add up all the variables.

FSD + FD + MSD + FS + MS + F + MD + M

62 + 45 + 87 + 96 + 275 + 88 + 227

880

5 0

3 years ago

in a window display at a flower shop, there are 3 spots for 1 plant each. to fill these 3 spots, adam has 7 plants to select fro

Andrej [43]

Answer: 210

Step-by-step explanation:

We know that the number of combinations of n things taken r at a time is given by :-

$C(n,r)=\dfrac{n!}{r!(n-r)!}$

So, number of ways to select 3 plants out of 7 = $C(7,3)=\dfrac{7!}{3!4!}=\dfrac{7\times6\times5\times4!}{6\times 4!}=7\times5=35$

Also number of ways to arrange them in 3 positions = 3! = 6

Now , total number of arrangements with 1 plant in each spot = (number of ways to select 3 plants out of 7) x (number of ways to arrange them in 3 positions)

= 35 x 6

=210

Hence, required number of ways = 210

5 0

3 years ago

Hii can someone pls help, I’m not sure what the answer is

konstantin123 [22]

Answer:

i think its quadratic

Step-by-step explanation:

4 0

3 years ago

Help me Find the answer, Here's the question!

Gelneren [198K]

Because the answers are all in standard form, we can simply look for the intercepts of the graph.

x-int = (-6, 0)
y-int = (0, -2)

You must multiply these numbers by a coefficient to equal 12:

$-6y = 12$
$-2x = 12$

Solve both equations by dividing by their values:

$y = -2$
$x = -6$

Look for the answer with these coefficients. The answer is -6x - 2y = 12.

6 0

3 years ago

(2.5×10-8)(9×10-10)​

(2.5×10-8)(9×10-10)