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Pavel [41]
3 years ago
13

Find the percent decrease. Round to the nearest percent. From 88°F to 64°F

Mathematics
1 answer:
lana [24]3 years ago
4 0

Answer:

27.3

(it's actually ~27.27)

You might be interested in
3. In AABC, a = 35, c = 25, and m can be drawn given these measurements?
Flauer [41]

Only one triangle possible with angle 38.2° at C.

According to the given statement

we have to seek out that the measurement of m with the help of the a and c.

Then for this purpose, we all know that the

The ambiguous case occurs when one uses the law of sines to see missing measures of a triangle when given two sides and an angle opposite one in every of those angles (SSA).

According to the this law

The equation become

35/sin(60) = 25/sinC

sinC = 0.6185895741

C = 38.2, 141.8

Since 141.8+60 = 201.8 > 180

It will not form a triangle.

So, only 1 triangle possible with angle 38.2° at C

Learn more about ambiguous case here

brainly.com/question/4372174

#SPJ1

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =35, c = 25, and m < A = 60*

How many distinct triangles can be drawn given these measurements?

6 0
1 year ago
Fred works as an
OLEGan [10]

Step-by-step explanation:

so he already down 20 ft so he ascends (goes up) 9 feet, so hes at 11 feet right now. then he descends 12 (goes down) feet so hes at 23 feet. lastly he ascends 15 feet (goes up) more. so the answer is 8

7 0
3 years ago
Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
Answer this question please and thank you
Murljashka [212]

Answer:

1

1

0

0

Step-by-step explanation:

here´s and example for 1

1⁵

1x1x1x1x1=1

so 1 raised to the power of any number is 1

1 multiply by itself any number of times is 1

here´s an example for 0

0⁴

0x0x0x0=0

hence, the vale of 0 raised to any power is 0.

0 multiplied by itself any number of times is 0

8 0
3 years ago
7.75 as fraction or mixed number
UNO [17]
It would be 7 with 75 over 100....it would look like 7 75/100. then simplify it.
4 0
3 years ago
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