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4 years ago

Let X and Y be the following sets: X={0,12,23} Y={3,12,15} Which of the following is the set X \ Y?

Mathematics

1 answer:

Digiron [165]4 years ago

8 0

Answer:

Step-by-step explanation:

X={0,12,23}

Y={3,12,15}

X \ Y = { 0 , 23}

X/Y means the element should be only in X. We have remove the element in X if it is in Y

In this 0 and 23 is only in X

12 is X and Y. So it wont come in X/Y

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Angle sum theorem y=? Degrees

strojnjashka [21]

Answer:

2x + 70 = 110

x = 20

Step-by-step explanation:

180-110 = 70

70 + 20 + y = 180

y =90

4 0

3 years ago

I really need help finding the solution!!

Mrac [35]

Answer:

-0.5 is not a solution

2 is a solution

Step-by-step explanation:

To check if something is a solution of the equation, you need to substitute the value in place of the variable

15 + 2y = -12 - 4y

15 + 2(-0.5) = -12 - 4(-0.5)

15 - 1 = -12 + 2

14 ≠ -10 ∴ -0.5 is not a solution

5 - 2(3x + 5) = 3 - 10x

5 - 2[3(2) + 5] = 3 - 10(2)

5 - 2(6 + 5) = 3 - 10(2)

5 - 12 - 10 = 3 - 120

-17 = -17 ∴ 2 is a solution

3 0

3 years ago

Income Taxes: Mastery Test

Margarita [4]

Answer:

1. tax deductions 2. the one that isn't amount of tax owed

Step-by-step explanation:

got the first part right and reviewed it on plato to see that The amount of tax owed is not the right answer.

4 0

2 years ago

Factor the Expression completely<br> -16x^2-6x^4

denpristay [2]

Answer: -2x^2 (3x^2 + 8)

Step-by-step explanation: a^b+c =a^b a^c

1) -16x^2 - 6x^ x^2

2) Rewrite -16 as -2 * 8

2.a Rewrite -6 as -2 * 3

= -2 * 8x^2 - 2 * 3x^2x^2

3) facter out common term: -2x^2

= ur answer

7 0

2 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

3 years ago