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Tresset [83]
3 years ago
7

Trying to solve a magic square

Mathematics
2 answers:
True [87]3 years ago
8 0

Answer:

google it?

Step-by-step explanation:

Free_Kalibri [48]3 years ago
8 0
(You answer needs to be at least 20 characters)
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18 = 3(3x – 6)<br> Step by step
butalik [34]
Start by multiplying 3 times 3x to get 9x. Then multiply 3 times -6 to get -18
After that your equation is 18=9x-18
Then your going to add 18 to each side so your equation should be 36=9x
Then devide each side by 9 so the answer will be x=4
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3 years ago
+3 + 3x2 – 2X-6<br> is this a prime polynomial
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8 0
2 years ago
Read 2 more answers
meteroloogist track severe stoms using Doppler radar. A polar grid is used to measure distances as the storms progress. If the c
FinnZ [79.3K]

Answer:

$(x-h)^2+(y-k)^2= (r+ 40 )^2$  

Step-by-step explanation:

It is given that a meteorologist is using a Doppler radar to find out the distance of the storm as it passes using a polar grid.

The origin of the radar screen is its center.

And the distance between each ring is 10 miles from the center.

So let :

r = radius

h and k = be the coordinates of the center.

So the equation of a circle is :

$(x-h)^2+(y-k)^2= r^2 $

Now the equation of the fourth circle when the radius changes by 10 miles is :

$(x-h)^2+(y-k)^2= (r+ 40 )^2$  

5 0
2 years ago
9- Jenny wants to buy a new camera. She found 4 stores that carry the camera
Vika [28.1K]

Answer:

d. $125, $135, $150, $130

Step-by-step explanation:

$125, $135, $150, $130

Range of the above set of numbers:

$150 - $125 = $25

Mean of numbers:

$125 + $135 + $150 + $130 = $540

540 ÷ 4 = $135

7 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
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