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balandron [24]
2 years ago
12

A northbound train and a southbound train meet each other on parallel tracks heading in opposite directions. the northbound trai

n travels 18 miles per hour faster than the southbound train. after 2 hours, they are 216 miles apart. at what speeds are the two trains traveling?
Mathematics
1 answer:
Vesna [10]2 years ago
3 0
Do the south 64 and then the 21 you never the .43
You might be interested in
Questions:
My name is Ann [436]

The  solution to the expressions given are;

9 -9t/ 12 - 5t

a. 20/ 169

b. -170/ 169

c.  386/ 169

d.  -10/ 169

<h3>How to solve the expressions</h3>

Given:

\frac{9 - 19t}{12 - 5t}

We can see that both variables in the numerator and denominator have no common factor, thus cannot be factorized further

a. \frac{203}{169} - \frac{183}{169}

First, let's find the lowest common multiple

LCM = 169

= \frac{203 - 183}{169}

= \frac{20}{169}

= 20/ 169

b. \frac{13}{119} - \frac{183}{119}

The lowest common multiple is 119

= \frac{13 - 183}{119}

substract the numerator

= - 170/ 119

c. \frac{203}{169} - \frac{183}{169}

The lowest common multiple is 169

= \frac{203 + 183}{169}

= 386/ 169

d. \frac{9}{169}- \frac{19}{169}

The lowest common multiple is 169

= \frac{9 - 19}{169}

= - 10/ 169

Thus, we have the solutions to be 9 -9t/ 12 - 5t, 20/ 169, -170/ 169, 386/ 169, -10/ 169 respectively.

Learn more about LCM here:

brainly.com/question/12732917

#SPJ1

7 0
1 year ago
What is the maximum area for a rectangle whose perimeter is 48 meters?
MakcuM [25]

Answer:

12m²

Step-by-step explanation:

For a rectangle, with length L and width W,

the perimeter is given as

Perimeter,

P = (2 x Length)  + (2 x Width)

P = 2L + 2W

It is given that the perimeter is 48, hence

48 = 2L + 2W   (divide both sides by 2)

24 = L + W

or

L = 24 - W -----> eq 1

Also realize that the Area of a Rectangle is given by

A = L x W  -----> eq 2

Substituting eq 1 into eq 2,

A = (24 - W) x W

A = -W² + 24W

Recall that for a quadratic equation y = ax² + bx + c, the maxima or minima is given by y(max) =  -b/2a

In this case, b = 24 and a = -1

-b/2a = -24/[ 2(-1) ] = 12

Hence for A to be maximum A(max) = 12m² (Answer)

5 0
3 years ago
What is the value of minus 6(-2)cubed - 4 squared - 3(-2x4)?
iogann1982 [59]

Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).

-6(-2)^2 - 4^2 - 3(-2x^4)

Multiply -6(-2)^2.

12^2 - 4^2 - 3(-2x^4)

Subtract 12^2 and -4^2.

8 - 3(-2x^4)

Distribute -3(-2x^4).

8 + 6x^4

Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.

6 0
3 years ago
(-5)2 - 2 x (-9) + 6​
Veronika [31]

Answer:

This is the answer

Step-by-step explanation:

6 0
2 years ago
If you add +6 +(-2), how many units will be between +6 and the sum ? Will the sum Be to the right or the left of +6 ? How do you
nikdorinn [45]
Draw a number line number it with negative number on the left and postive numbers at the right start at postive 6 now go to the left twice your answer should be 4
5 0
3 years ago
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