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Korvikt [17]
3 years ago
15

Can someone help me with this question please?

Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

  0.15 for each message

Step-by-step explanation:

The charge per message can be found by dividing the charge by the number of messages. Using the first line of the table, we get ...

  charge per message = (total charge)/(number of messages) = $38.40/256

  charge per message = $0.15

Alyssa is charged 0.15 for each text message.

_____

We can check other lines of the table to see if charges are really proportional:

  $26.55/177 = $0.15

  $31.35/209 = $0.15

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Step-by-step explanation:

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Solving the whole thing
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Let
x---------------> distance from people living to the city center

we Know that
Zone 1 covers people living within three miles of the city center
Zone 1 ------------> [x < 3 miles]

Zone 2 covers those between three and seven miles from the center
Zone 2 ------------> [ 3 <= x < = 7  miles]

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Zone 3 ------------> [  x > 7  miles]

<span>calculate the distance between two points to find the value of x
</span>
case A) point (0,0)  point (3,4)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(4-0)² +(3-0)²]------> √[16+9]
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the answer Part A)
people living in (3,4)
x=5 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]


case B) point (0,0)  point (6,5)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(5-0)² +(6-0)²]------> √[25+36]
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case C) point (0,0)  point (1,2)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(2-0)² +(1-0)²]------> √[4+1]
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the answer Part C)
people living in (1,2) 
x=2.23 miles -------------> covers Zone 1 [ x < 3  miles]

case D) point (0,0)  point (0,3)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(3-0)² +(0-0)²]------> √[9]
x=√9-------------> x=3 miles

the answer Part D)
people living in (0,3) 
x=3 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]

case E) point (0,0)  point (1,6)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(6-0)² +(1-0)²]------> √[36+1]
x=√37-------------> x=6.08 miles

the answer Part E)
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2) The expression inside the absolute value symbol is a negative number, then :

|-x|=x\\

and replacing it in the equation, this becomes:

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