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Lubov Fominskaja [6]
3 years ago
9

Which is an example of an operation? A. Y B. 6ab C. + D. 12

Mathematics
2 answers:
kirza4 [7]3 years ago
5 0
The answer is c. Multiplication, addition, division, and subtraction are all examples of operations
Svetllana [295]3 years ago
4 0
I believe the answer should be c
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If the perpendicular bisector of one side of a triangle goes through the opposite vertex, then is the triangle ( sometimes, alwa
avanturin [10]
It is always isosceles because it can be proved as follows:

The perpendicular bisector dissects the triangle into two, and it is the common side.  Then each side of the bisector is 90 degrees, and the bisected to two equal sides, so the two dissected triangles are congruent, hence the original triangle is isosceles.
7 0
3 years ago
A. 1/36<br> B. 1/18<br> C. 1/3<br> D. 1/6
lara31 [8.8K]

Answer:

C

because it looks right

7 0
3 years ago
Read 2 more answers
Help Pls! I need this fast!
lesya [120]

Answer: 36

Step-by-step explanation:

\overline{AB} \cong \overline{BC} (Triangle ABC is isosceles)

m\angle CAB=m\angle CBA=30^{\circ} (base angles of an isosceles triangle are congruent)

\angle MCB=90^{\circ} (In triangle CMB, angles in a triangle add to 180 degrees)

\angle ACM=30^{\circ} (triangle sum theorem)

MB=24 (30-60-90 triangle CMB)

AB=12 (sides opposite congruent angles in a triangle are congruent)

AB=36 (segment addition postulate)

3 0
2 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
Find the area of a triangular prism
saveliy_v [14]
In order to calculate the area of a triangular prism, You can use the formula,

Area = 1/2 * a * c * h

Hope this helps!
7 0
3 years ago
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