Answer:
Normal distribution table
Step-by-step explanation:
We need to define all the variables that are presented to us in the problem, like this:
Data point in question = xi = 36000
The mean = μ = 32000
The standar variation = s = 3000
calculate the z-score for the left bound
x = 36000:
![z = \frac{x_{i}-\mu}{\frac{s}{\sqrt{n}} }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7Bx_%7Bi%7D-%5Cmu%7D%7B%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D%20%7D)
where μ = 32000, s = 3000, n = 1. (There is only one
teacher in the sample.)
z-score for 36000 is calculated thusly:
![z = \frac{36000-32000}{3000} =1.3333](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B36000-32000%7D%7B3000%7D%20%3D1.3333)
It is necessary to look in the normalized table for this value, and look in the area on the left that for 1.33 the result is 0.9082
<em>So our probability is 0.9082 that he or she makes more than $36000</em>
Answer:
63.25 sq. ft
Step-by-step explanation:
the area of fig. =
(½×8×6)+(½×3.14×5²)
= 24 + 39.25
= 63.25 sq. ft
Exterior angles are found along the outside of the figure if you extend the figure's side lengths.
The exterior angles in the image would be 4 and 5.
6 isn't an angle, and all of the other options are found on the inside of the triangle (1,2 and 3).
The answer to your question is B
Yes, because we have the number ‘e’ raised to x, although it is now -3x, it is still a variation of x