Answer:
2x−3y=6
Step-by-step explanation:
Explanation:
Standard form: Ax + By = C
Just take 2/3x to the other side.
So the answer would be −23x+y=−2
But not yet the final answer... In standard form x can't be negative and A, B and C need to be an integers (whole numbers)
(I multiplied the whole equation by -3)
2x−3y=6
Answer:
Step-by-step explanation:
Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)
Answer:
£78.97
Step-by-step explanation:
The average train ticket for the journey, including cycle storage costs and food and drink,<u> costs £134.26</u>. A coach company claims that it is <u>£55.29 </u><em><u>cheaper</u></em><u> than this</u>. How much does the coach trip cost?
Cheaper = -
So 134.26-55.29=78.97
Answer:
Step-by-step explanation:
2, -3 , -8 , -13 , - 18 .............
This is an arithmetic sequence.
First term = a = 2
Common difference = Second term - first term
= -3 - 2 = -5
Nth term = a + (n - 1)*d
= 2 + (n - 1)*(-5)
= 2 + n*(-5) - 1 *(-5)
= 2 - 5n + 5
= 7 - 5n
n = 19,
19th term = 7 - 5*19
= 7 - 95
= - 88
n = 21,
21st term = 7 - 5*21
= 7 - 105
= -98
