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kirill [66]
3 years ago
7

Your company purchase a 12 month insurance policy for $36000 in January

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Question is incomplete

Your company purchased a twelve-month insurance policy for $36,000 in January. What's the entry to record the monthly insurance expense in March?

Answer:

Date Account and explanation

Insurance expense $3,000 (Debit)

Prepaid insurance $3,000 (Credit)

Step-by-step explanation:

Given

Insurance Policy = $36,000

Duration = 12 months

First we calculate the monthly entry.

This is calculated by dividing the cost of insurance policy by the duration.

Monthly Expenses = Cost / Number of months

Expenses = $36,000/12

Expenses = $3,000

The entry to record the monthly insurance expense in March is as follows

Date Account and explanation

Insurance expense $3,000 (Debit)

Prepaid insurance $3,000 (Credit)

bearhunter [10]3 years ago
7 0

please complete the question

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Please help I got stuck on this on thank you
svetlana [45]
Answer is B. 3

2/3 x 3  = 6/3 = 2 cups
7 0
3 years ago
A construction crew has repaired 1.37 miles of a highway. The total length of the highway to be repaired is 7.9. How many miles
JulijaS [17]

Answer:

Part A: m+1.37=7.9

Part B: 6.53 miles are left to be repaired.

Step-by-step explanation:

Given,

Length of repaired part = 1.37 miles

Total length to be repaired = 7.9 miles

Miles left to be repaired = m

Part A:

Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.

Miles left to be repaired + Length of repaired part = Total length to be repaired

m+1.37=7.9

Part B

How many miles are left to be repaired?

Subtracting 1.37 from both sides

6.53 miles are left to be repaired.

Keywords: length, subtraction

Step-by-step explanation:

6 0
3 years ago
What is equivalent to 35d-25
baherus [9]

Answer:

5(7d-5)

Step-by-step explanation:

taking 5 common from  35d-25

= 5(7d- 5)

7 0
3 years ago
Read 2 more answers
How many 16-ounce bottles would be needed to hold the same total amount of water 56 bottles that each holds 20 ounces
snow_lady [41]

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Step-by-step explanation:

Given,

56 bottles hold 20 ounces each.

Total amount 56 bottles hold= 56x20

Total amount hold by 56 bottles= 1120 ounces

Let the number of 16 ounces bottles be = x

Total amount hold by x bottles = 16x

According to the given statement both amounts are same;  

16x=1120\\Dividing\ both\ sides\ by\ 16\\\frac{16x}{16} = \frac{1120}{16} \\x=70

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Keywords: Division, Multiplication

Learn more about division at:

  • brainly.com/question/2035523
  • brainly.com/question/2088305

#LearnwithBrainly

6 0
3 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
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