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Dominik [7]
2 years ago
15

Suppose Cesar Chavez lead a March with 6,300 people. If the ratio of marchers who were not farmworkers to farmworkers is 4:5, ho

w many of the marchers were farmworkers?
Mathematics
1 answer:
baherus [9]2 years ago
4 0

Answer:

3500.

Step-by-step explanation:

We have been given that Cesar Chavez lead a March with 6,300 people. The ratio of marchers who were not farm-workers to farm-workers is 4:5. We are asked to find the number of marchers, who were farm-workers.

First of all, we will find the ratio of farm-workers to total marchers as:

\frac{\text{Farm-workers}}{\text{Total marchers}}=\frac{\text{Farm-workers}}{\text{Farm-workers+non-farm-workers}}=\frac{5}{4+5}=\frac{5}{9}

To find the number of marchers, who were farm-workers, we need to find \frac{5}{9} of whole marchers.

\text{Number of marchers that were farm-workers}=6300\times \frac{5}{9}

\text{Number of marchers that were farm-workers}=700\times \frac{5}{1}

\text{Number of marchers that were farm-workers}=3500

Therefore, 3500 marchers were farmers.

 

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Answer:

C = 82

Step-by-step explanation:

Given

R = 5\% -- Rate

P = 800 -- Principal

N = 2 -- Time

Required

Determine the compound interest

First, we calculate the Amount (A)

A = P(1 + R)^N

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Express % as decimal

A = 800*(1 + 0.05)^2

A = 800*(1.05)^2

A = 882

The compound interest (C) is then calculated as:

C = A -P i.e. Amount - Principal

C = 882 - 800

C = 82

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