All categories

2 years ago

The radius of a circle is 16 cm. Find its area in terms of pi

Mathematics

1 answer:

anzhelika [568]2 years ago

8 0

Area is 804.25 if the radius is 16cm

You might be interested in

The function for the cost of materials to make a muffin is f(x)=3/4x+3, where x is the number of muffins. The function for the s

scoray [572]

the first one is from walmart which is 5.99$ the other store sells it for 3.49 which one is better to buy

8 0

2 years ago

he says the number of books in the box is divisible by 2,3,4,5,6 . how many books could be in the box?

8_murik_8 [283]

The least number of books that could be in the box is 30. The number of books in the box could be any number that is a multiple of 30.

7 0

2 years ago

What is the slope? y = 3 1 2 3 0

inysia [295]

Answer:

Step-by-step explanation:

there are 6 birds and you add 7 and this is what you get

8 0

2 years ago

ou find a clue wrapped around a Toblerone bar. The base was an equilateral triangle with a side of 16 mm and the bar was 155 mm

qwelly [4]

Answer:

54 cubic inches?

Step-by-step explanation:

7 0

3 years ago

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV

JulijaS [17]

Answer:

$\frac{dT}{dt}=3.78^{\circ}K/min$

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

$\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}$

What we have to do is the derivative of a product:

$\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}$

Substituting, we have:

$\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}$

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

$\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}$

And then just calculate:

$\frac{dT}{dt}=3.78^{\circ}K/min$

6 0

2 years ago