Answer:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
4 1/3 can be separated into 4, and 1/3.
half of 4 is 2.
Half of 1/3 is 1/6.
Add 2 and 1/6, and you get 2 and 1/6. Answer is C
Answer:
Step-by-step explanation:
Put these numbers into their prime factors.
18: 2 * 3 * 3
27: 3 * 3 * 3
12: 2 * 2 * 3
The LCM must have
two 2s
Three 3s
That's it
2*2 * 3 * 3 * 3
LCM = 108
648 might be a multiple of the three, but it's not the smallest one.
108 = 27 * 4
108 = 18 * 6
108 = 12 * 9
Answer:
10
Step-by-step explanation:
