A nominal has three terms.
Only B and D have three terms.
A constant term would be a number without a variable.
All the terms in B have variables ( x , y are part of each term).
The last term in D is the number 12, with no variable associated with it.
The answer would be D.
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Step-by-step explanation:
so, just by getting into the taxi we have to pay R10.
that leaves us 22 - 10 = R12 for the actual trip.
30 cents per kilometer.
so, how many units of 30 cents are there in R12 ? that is the number of kilometers we can go.
R12 = 1200 cent (right ?)
1200 / 30 = 120 / 3 = 40
so, we can travel 40 kilometers for that money.
Divide both the numerator and denominator by the GCD so it’s 12/1
Well 22/7 is 3.14 and so on but since there is a little more than 3 you need to make sure he covers up all the fencing places... SO John will need 4 fences