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aleksklad [387]
3 years ago
13

Please help!

Mathematics
2 answers:
kramer3 years ago
7 0

Step-by-step explanation:

We are given two angles measures and one side. Notice the given angle and the side that is opposite to that given angle is given. We need to find side x. But can we also find the angle opposite of the side we are trying to find. Yes we can

<em>Remeber that triangles interior angles add up to 180.</em>

<em>Remeber that triangles interior angles add up to 180.One angle measure 90 and the other measure is 57 so</em>

<em>90 + 57 + x = 180</em>

<em>x = 33</em>

<em>So</em><em> </em><em>the</em><em> </em><em>angle</em><em> </em><em> </em><em>opposite</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>side</em><em> </em><em> </em><em>we</em><em> </em><em> </em><em>are</em><em> </em><em>trying</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>is</em><em> </em><em>33</em><em>.</em>

Since we know two angles and two sides that are opposite of those two angles respectively, we can use what is called Law of Sines

\frac{b}{ \sin(b) }  =  \frac{c}{ \sin(c) }

where the numerator are the side measures, and the denominator are the angle measures.

Plug in the respectively values. Angle 57 is opposite of 10 and Angle 33 is opposite of x.

\frac{10}{ \sin(57) }  =   \frac{x}{ \sin(33) }

Multiply both sides by sin 33 to isolate x.

We get

x = 6.494

Round if needed

In other words, apply law of sines when you have two angles and two sides that are opposite of those angles respectively.

Darya [45]3 years ago
6 0

Answer:

x = 6.5

Step-by-step explanation:

In order to solve this problem, you need to use trigonometry (sin, cosine, tangent).  

Sin = opposite/hypotenuse

Cosine = adjacent/hypotenuse

Tangent = opposite/adjacent

We need to use tangent in this case because 10 is the opposite side from the 57° angle, and x is right next to it, making it adjacent.  So, our equation would look like this:

tan (57)° = 10/x

Multiply both sides by x

x (tan (57)°) = 10

Divide both sides by tan (57)°

10 / tan (57)° = 6.49408 = 6.5

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A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)equals72 com
solmaris [256]

Answer:

Part (A)

  • 1. Maximum revenue: $450,000

Part (B)

  • 2. Maximum protit: $192,500
  • 3. Production level: 2,300 television sets
  • 4. Price: $185 per television set

Part (C)

  • 5. Number of sets: 2,260 television sets.
  • 6. Maximum profit: $183,800
  • 7. Price: $187 per television set.

Explanation:

<u>0. Write the monthly cost and​ price-demand equations correctly:</u>

Cost:

      C(x)=72,000+70x

Price-demand:

     

      p(x)=300-\dfrac{x}{20}

Domain:

        0\leq x\leq 6000

<em>1. Part (A) Find the maximum revenue</em>

Revenue = price × quantity

Revenue = R(x)

           R(x)=\bigg(300-\dfrac{x}{20}\bigg)\cdot x

Simplify

      R(x)=300x-\dfrac{x^2}{20}

A local maximum (or minimum) is reached when the first derivative, R'(x), equals 0.

         R'(x)=300-\dfrac{x}{10}

Solve for R'(x)=0

      300-\dfrac{x}{10}=0

       3000-x=0\\\\x=3000

Is this a maximum or a minimum? Since the coefficient of the quadratic term of R(x) is negative, it is a parabola that opens downward, meaning that its vertex is a maximum.

Hence, the maximum revenue is obtained when the production level is 3,000 units.

And it is calculated by subsituting x = 3,000 in the equation for R(x):

  • R(3,000) = 300(3,000) - (3000)² / 20 = $450,000

Hence, the maximum revenue is $450,000

<em>2. Part ​(B) Find the maximum​ profit, the production level that will realize the maximum​ profit, and the price the company should charge for each television set. </em>

i) Profit(x) = Revenue(x) - Cost(x)

  • Profit (x) = R(x) - C(x)

       Profit(x)=300x-\dfrac{x^2}{20}-\big(72,000+70x\big)

       Profit(x)=230x-\dfrac{x^2}{20}-72,000\\\\\\Profit(x)=-\dfrac{x^2}{20}+230x-72,000

ii) Find the first derivative and equal to 0 (it will be a maximum because the quadratic function is a parabola that opens downward)

  • Profit' (x) = -x/10 + 230
  • -x/10 + 230 = 0
  • -x + 2,300 = 0
  • x = 2,300

Thus, the production level that will realize the maximum profit is 2,300 units.

iii) Find the maximum profit.

You must substitute x = 2,300 into the equation for the profit:

  • Profit(2,300) = - (2,300)²/20 + 230(2,300) - 72,000 = 192,500

Hence, the maximum profit is $192,500

iv) Find the price the company should charge for each television set:

Use the price-demand equation:

  • p(x) = 300 - x/20
  • p(2,300) = 300 - 2,300 / 20
  • p(2,300) = 185

Therefore, the company should charge a price os $185 for every television set.

<em>3. ​Part (C) If the government decides to tax the company ​$4 for each set it​ produces, how many sets should the company manufacture each month to maximize its​ profit? What is the maximum​ profit? What should the company charge for each​ set?</em>

i) Now you must subtract the $4  tax for each television set, this is 4x from the profit equation.

The new profit equation will be:

  • Profit(x) = -x² / 20 + 230x - 4x - 72,000

  • Profit(x) = -x² / 20 + 226x - 72,000

ii) Find the first derivative and make it equal to 0:

  • Profit'(x) = -x/10 + 226 = 0
  • -x/10 + 226 = 0
  • -x + 2,260 = 0
  • x = 2,260

Then, the new maximum profit is reached when the production level is 2,260 units.

iii) Find the maximum profit by substituting x = 2,260 into the profit equation:

  • Profit (2,260) = -(2,260)² / 20 + 226(2,260) - 72,000
  • Profit (2,260) = 183,800

Hence, the maximum profit, if the government decides to tax the company $4 for each set it produces would be $183,800

iv) Find the price the company should charge for each set.

Substitute the number of units, 2,260, into the equation for the price:

  • p(2,260) = 300 - 2,260/20
  • p(2,260) = 187.

That is, the company should charge $187 per television set.

7 0
3 years ago
Note: You may use a calculator to solve the following problems. If 1 kilogram = 2.206 pounds, how many pounds are in a gram?
tiny-mole [99]
Your answer would be D) <span>2.206! good luck 
x</span>
4 0
4 years ago
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