F(2)=20(1.25)^x STEP BY STEP
2 answers:
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I started with c, but you could’ve started with any box.
So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.
Then I went to a. All of a’s numbers were divisible by 7.
Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!
Then d. Two are divisible by 7, so your rules is divisible by 2.
I hope this helps!
So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.
Then I went to a. All of a’s numbers were divisible by 7.
Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!
Then d. Two are divisible by 7, so your rules is divisible by 2.
I hope this helps!
We have a probability of for the first card to be a diamond. Having drawn this first card <em>without replacement,</em> there are now 12 diamonds remaining in a deck of 51 cards, so the probability that the second card is a diamond, given that the first card was a diamond, is
Similarly, for the third card, there are 11 diamonds in a deck of 50, so the probability of drawing a third diamond is
Now, since these events are dependent, we multiply these three probabilities to get our answer of