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olganol [36]
2 years ago
7

Will mark BRAINEST please help solve for x

Mathematics
1 answer:
zheka24 [161]2 years ago
5 0

Answer: Your answer is 32

Step-by-step explanation: Pls mark me as brainiest and your welcome

.

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**HELP MEEEE!! NEED ANSWERE ASAP!!!!**
Stells [14]

The first one is -8+2 = -6

And the second one is 2 x 2 = 4

3 0
3 years ago
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If log10x=−3 , what is the value of x ?
IgorC [24]

log10x=−3

10 ^(log10x) = 10^(-3)

10x = 10^-3

x =10 ^ -3 / 10

x = 10^-4

x = .0001

x=1/ 10000

6 0
3 years ago
4
Fudgin [204]

Answer:

x=4

Step-by-step explanation:

The y axis is a line where the value of x does not change ( x=0)

It is a vertical line

The only line where the value of x does not change is x=4

It is a vertical line at x=4

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3 years ago
lone star supply company bought a computer system with a color monitor for 1,598 if the color monitor cost $699 how much did the
ladessa [460]

Answer: $899

Step-by-step explanation: I subtracted $699 from $1598 so it would look like this

$1598-$699=$899

5 0
3 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
Read 2 more answers
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