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3 years ago

Find the area of the trapezoid 36mm by 15mm by 14mm.

Mathematics

2 answers:

neonofarm [45]3 years ago

7 0

Answer:

1428mm

Step-by-step explanation:

Area = 0.5 (a + b) h

Area= 0.5 (36 + 15) 14

Area = 0.5 ( 51) 14

Area = 1428 mm or 1.428m

tatyana61 [14]3 years ago

6 0

Answer:

i think it is 357 hope this helps

Step-by-step explanation:

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Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil

KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

= 6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

= 9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

= 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

= 4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

= 4.5 days to get to the next pond.

3 0

3 years ago

Find the distance BF for the points B(1,-1) and F(-3,5)

Nadusha1986 [10]

Use the distance formula:
 $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Plug in the given coordinates:
 $\sqrt{(-3-1)^2 + (5-(-1))^2}$

Simplify:
 $\sqrt{(-3-1)^2 + (5+1))^2}$

$\sqrt{-4^2+ 6^2}$

$\sqrt{16+36}$

$\sqrt{52}$
You can leave it as: $\sqrt{52}$ or in decimal form as: 7.2

6 0

4 years ago

A cable is 84 meters long, it is cut into two pieces so that one piece is 18 meters longer than the other. Find the length of ea

weeeeeb [17]

Long Piece: x + 18

Short Piece: x

(x) + (x + 18) = 84

2x + 18 = 84

2x = 66

x = 33

Long Piece: x + 18 = (33) + 18 = 51

Answer: 33 meters and 51 meters

5 0

4 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

Step-by-step explanation:

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago

A nut mixture of peanuts and macadamia nuts at a small fair is $1.00 per pound of peanuts and $3.26 per pound of macadamia nuts.

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

You can infer to the solution of this problem by looking at the choices. Hope this helped :)

7 0

3 years ago