Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
By rearranging it:
-3x-2x-22xy+4y
=-5x-22xy+4y answer
Answer: $2394.43
explanation: use equation A=Pe^rt. A=2000e^(0.03x6). A=2394.43
Answer:
a = M -Gh/G
Step-by-step explanation:
in order to make a the subject of fomular , you will open the bracket first and then combine the like terms.
G(a + h) = M
Ga + Gh = M
Ga = M - Gh
since G is disturbing a from standing alone, we divide both sides by G
Ga/G = M- Gh/ G
a = M -Gh/G
