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rosijanka [135]
2 years ago
8

For what value of c is the relation a function?

Mathematics
1 answer:
nydimaria [60]2 years ago
7 0

Answer:

{ c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

Step-by-step explanation:

Considering the set

\left\{\left(2,\:8\right),\left(12,\:3\right),\:\left(c,\:4\right),\:\left(-1,\:8\right),\:\left(0,\:3\right)\right\}

As we know that

  • A function is said to be a relation if every x-value has one and only one y-value.

So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0

Therefore,

                   { c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

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lozanna [386]

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Step-by-step explanation:

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Use long division. After using decimal point at the top we can include any number of zeros with 719

                            . 1 2 3 9

                        ---------------------

        5800         7190

                          5800

                     ------------------------(subtract)

                          13900

                          11600

                       ---------------------------(subtract)

                           2300 0

                           1740 0

                       --------------------------(subtract)

                            56000

                            52200

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                             3800 0

Division goes on ............

Estimate the quotient to 3 decimal places

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3 years ago
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