1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mkey [24]
3 years ago
7

Which pair of equations generates graphs with the same vertex?

Mathematics
2 answers:
Elza [17]3 years ago
4 0

Answer:

b

Step-by-step explanation:

lesya692 [45]3 years ago
3 0
B is the answer to the question
You might be interested in
Hey guys what is this type of equation/ question called 1 < x < 30
dimulka [17.4K]

Answer:

2,3,4,5,6,7,8,9,10,...29

Step-by-step explanation:

6 0
3 years ago
Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari
Ulleksa [173]

Answer:

(a)E[X+Y]=E[X]+E[Y]

(b)Var(X+Y)=Var(X)+Var(Y)

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).

Since f(X,Y)=X+Y

E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).

Let us look at the first of these sums.

\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].

Similarly,

\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].

Combining these two gives the formula:

\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)

Therefore:

E[X+Y]=E[X]+E[Y] \text{  as required.}

(b)We  want to show that if X and Y are independent random variables, then:

Var(X+Y)=Var(X)+Var(Y)

By definition of Variance, we have that:

Var(X+Y)=E(X+Y-E[X+Y]^2)

=E[(X-\mu_X  +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2  +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2  +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2  +E[Y- E(Y)]^2+2Cov (X,Y)

Since X and Y are independent, Cov(X,Y)=0

=Var(X)+Var(Y)

Therefore as required:

Var(X+Y)=Var(X)+Var(Y)

7 0
3 years ago
(9+8)+32=49 which property is this
Sergio [31]
Associativity means
(A+B)+C=A+(B+C)=A+B+C

Substitute A=9, B=8, C=32 to apply to this problem.
6 0
3 years ago
All of the following operations are used to solve for X in the equation below except one. Which one is it ? 9x-2=4x+8 A. Additio
gtnhenbr [62]

Step-by-step explanation:

9x - 2 = 4x + 8 → (9-4)x = 8 + 2 → 5x = 10 → x = 10/2 = 5

C. multiplication

Multiplication not used

5 0
3 years ago
Three billion sixty million sixty six thousand nine hundred ​
Anestetic [448]

Answer:

3,000,000,000

60,000,000

66,000

900

Step-by-step explanation:

3,060,066,900

:)I dont know is C

8 0
3 years ago
Other questions:
  • Which set of three angles could represent the interior angles of a triangle? 26 degrees, 51 degrees, 103 degrees 29 degrees, 54
    11·2 answers
  • Which expression are equivalent 10
    6·1 answer
  • A researcher selects all of the possible samples with n = 8 scores from a population and computes the mean, dividing by n, for e
    14·1 answer
  • HELP DUE IN 10 MINS! Solve for x in the parallelogram below:<br><br> x=??
    15·2 answers
  • If I need a big toilet how much money will it be the average is 100 money but I need 100 times that!!!!
    6·1 answer
  • I DONT HAVE MUCH TIME TO SUBMIT THIS CAN ANYONE HELP!?!
    12·1 answer
  • Jana is buying a cell-phone plan. She has two plans to choose from.
    8·1 answer
  • .Solve 5x – 3y = 9 for y
    7·1 answer
  • How many times greater than √2 is√32?<br><br> Can anybody help out here?
    5·2 answers
  • ( 6x-y) ( 1/3x² + y²) mutiply the following​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!